datediff snowflake. g. datediff snowflake

 
gdatediff snowflake  Answer

select ADD_MONTHS(CURRENT_DATE,-1) as result; The main difference between add_months and dateadd is that add_months takes less parameters and will return the last day of the month for the resultant month if the input date is also the last day of the month,We would like to show you a description here but the site won’t allow us. 0 is for 1/1/1900, and getdate is the current date --(i used a set date bc dates will change as this post gets older). 2. I am looking to understand what the average amount of days between transactions is for each of the customers in my database using Snowflake. Arguments¶ percentile. You'll get a more accurate result if you compute the difference between the two dates in days and divide by the mean length of a calendar year in days over a 400 year span (365. From the inputs you got there are 123 months between the date of 07/03/2011 to 24/3/2021. The units are used is a Date part ( year, month, date ) or Time part (hours, minute, second). Unfortunately, the naive approach with the DATEDIFF() function doesn't quite cut it here - using DATEDIFF('year', birthday, current_date) nets the difference between the current year and the birthday year, which could be a very inaccurate representation of the. In this article, Let us see a Spark SQL Dataframe example of how to calculate a Datediff between two dates in seconds, minutes, hours, days, and months using Scala language and functions like datediff(), unix_timestamp(), to_timestamp(),. g. これは、追加する時間単位を示します。例えば、2日を追加する場合、これは DAY になります。 この測定単位は、 サポートされている日付と時刻の部分 にリストされている値のいずれかでなければなりません。 valueUsage Notes¶. The default is month. datediff(part: str, col1: Union[Column, str], col2: Union[Column, str]) → Column[source] Calculates the difference between two date, time, or timestamp columns based on the date or time part requested, and returns result of col2 - col1 based on the requested date or time part. Supported date and time parts. To calculate the difference between two timestamps, convert them to unix timestamps then subtract: Master date and time queries in Snowflake with our comprehensive guide. by date or location). String concatenation will build '1' + ',' + '27'. For seconds: DATEDIFF (second, LAG (ACTION_DATE) OVER (PARTITION BY users ORDER BY ACTION_DATE), ACTION_DATE ) AS DIFF_SECONDS. An alternative sql only solution - start and end dates go into the current_date() spots. This is the date or timestamp expression to which you want to add a specified number of months. TIME_SLICE calculates the beginning or end. Fractional seconds are not rounded. Snowflake does not allow to run session variable statement and dashboard query statement together. approx_percentile_combine. Didn't know that. The LAG function is getting the second, third, fourth, fifth, sixth and seventh rows of data based upon the udid. g. O sinal de menos (-) também pode ser usado para subtrair datas. snowflake-cloud-data-platform; Share. 124 seconds. SELECT (DATEDIFF (dd, LossDate, ClaimDate) + 1) - (DATEDIFF (wk, LossDate, ClaimDate) * 2) - (CASE WHEN DATENAME (dw, LossDate) = 'Sunday' THEN 1 ELSE 0 END) - (CASE WHEN DATENAME (dw, ClaimDate) = 'Saturday' THEN 1 ELSE 0 END). For DATEDIFF: date_or_time_expr1 and date_or_time_expr2 can be a date, time, or timestamp. snowpark. Sql. The function supports units of years, quarters, months, weeks, days, hours, minutes, seconds, milliseconds, microseconds, and nanoseconds. Recent Snowflake feature improvements mean that it’s becoming easier to generate monitoring and administrative email notifications from within the platform. Image file. -6. To Here is an example of changing a TIMEZONE at the session level: ALTER SESSION SET. For DATEDIFF: date_or_time_expr1 and date_or_time_expr2 can be a date, time, or timestamp. The fact that the function returns an integer number of months both when the days of the month are the same (e. 0. Is there a way around this, or a way to predetermine which date is null up front? (psudocode)TO_DATE , DATE. When calculating it, only from 9am till 17pm and weekdays are needed to be accounted. June 3-6, 2024. convert(varchar,cast((End_Datetime-Start_Datetime) as time),108) how to convert this to snowflakesnowflake. For a variant expression: If the variant contains a string, a string conversion is performed. columns WHERE table_name = 'hrStaff'. where (DateDiff (d, FilteredPhoneCall. snowflake. Many applications use date functions to manipulate the date and time data types. 0 to 23. EXTRACT. When using datediff to calculate a year, it only looks at the year. [NEXT PAYMENT DUE DATE], getdate()) > 90 but this is not working in Snowflake. So, i think, hive considers date + time difference but snowflake consider only date part and time part is ignored. Start Date & End Date should be Min & Max dates of Sales Fact Table. id , sum (datediff (‘second’, -- calculate the max of the two start time (case when t. DATEADD function Arguments date_or_time_part. What is the difference between Snowflake DATEDIFF() and DATEADD()? Snowflake DATEDIFF() calculates the difference between two dates, while DATEADD(). To get the number of full time units passed between datetimes, you can calculate the difference in lower units and then divide by the appropriate number. MINUTE. In your example your interval duration is 1 hour. functions. The function returns the result of. 5 * FLOOR ((DATEDIFF (day, date_trunc ('quarter', @s), @e)). These functions are alternatives to using the DATE_PART (or EXTRACT) function with the equivalent date part (see. I'm trying to figure out how to find "DATEDIFF" between several events in a data set for a specific value (Article No). The value can be a string literal or an expression that returns a string. This function can be used to calculate the start and end times of fixed-width “buckets” into which data can be categorized. g. functions. This allows you to ensure that the data changes made by the stored procedure are consistent and atomic. From fetching the current timestamp to calculating date differences, we've got you covered. I am new to snowflake. The closest I've come is FLOOR. While I've solved their problem, It came about that I don't actually know what the 0 turns into when used as they were using it. There are 3 different timestamp types in Snowflake: TIMESTAMP_NTZ. CREATE TABLE t (id int, creation_date VARCHAR (19. My Snowflake SQL Query : SELECT O. : pip install data-diff 'data-diff [postgresql,snowflake]' -U. , DATEDIFF and DATEADD). SELECT DATEADD(WEEK, DATEDIFF(WEEK,0,GETDATE()),-3) But based on my reading and some SQL Fiddle, it seems to output the start of "this week" minus 3 days. I use the following where condition as 0 to select the value on today's date. Uses snowflake procedures to build and (daily)rollover of the the definition of current date, week, month etc. SELECT DATEDIFF (DAY, xx, yy) AS Avg_DayDiff FROM Database1. (SELECT DATEDIFF(second ,CREATED. DATE_TRUNC. . The ORDER BY and LIMIT / FETCH clauses are applied to the result of the set operator. Then you try to use this number with the DATEADD function, and it expects to have a date instead. The * tells Snowflake to look at all columns, but you could have put just one column as it means the same thing. More from Mike Diaz. I'm having trouble getting it to run in snowflake. BUT now I'm trying to code like this: coalesce (datediff (day, to_date (datvr::varchar, 'YYYYMMDD'), to_date (datvrn::varchar, 'YYYYMMDD')), 0) DAYSTONEXTPO. Like Liked Unlike Reply. Step 5: Move the Existing Data Set After your database objects are created in Snowflake, the next step is to move the historical data to Snowflake. g. Expand Post. DATEDIFF(MONTH, 0, '2-14-2015') --returns month. Please find the sample table contents below. date_to, DATEDIFF(DD, evnt. approx_percentile_estimate. INTERVAL data types aren’t supported in Snowflake, but date calculations can be done with the date comparison functions (e. For example, -0. If the value of Nweek = '201834' then the value of IDate is returned as '2018-08-20' If the value of Nweek =. 이 함수는 연도, 분기, 월, 주, 일, 시간, 분, 초, 밀리초, 마이크로초, 나노초 단위를 지원합니다. I want to find the time difference between two timestamps for each id . Assuming that end_datetime and start_datetime are a datetime or timestamp field, you can just use the datediff() function:. This is how I was able to generate a series of dates in Snowflake. DATETIME is an alias for TIMESTAMP_NTZ. functions. The date is complete (year, month, and day). I want to be able to compare the date between the first record and any future records for that card id where that future record's legit = 0, and if the first record is within 10 days, show that record. you ca also use LAG analytical function to get the desired results as : Suppose below is your input table: id account_number account_date 1 1001 9/10/2011 2 2001 9/1/2011 3 2001 9/3/2011 4 1001 9/12/2011 5 3001 9/18/2011 6 1001 9/20/2011 select id,account_number,account_date, datediff(day,lag(account_date,1) over (partition by. DATEDIFF(MONTH, 0, @date), 0) AS First_Day_of_Month SELECT @date - DAY(@date) + 1 AS FIRST_DAY_OF_DATE -- In SQL Server 2012 and above SELECT DATEADD(DAY, 1, EOMONTH(@date, -1)). I have used the code contained below to create date and time scaffolds for several clients for various reasons, such as populating records between the “CreateDate” and “CloseDate” of a data point. About; Products For Teams; Stack Overflow Public questions & answers; Stack Overflow for Teams Where developers & technologists share private knowledge. 複数の行が評価される場合(例: 入力が複数の行を含むテーブルの列名である場合)、値が秒. GENERATOR. To comply with ANSI standards, this function can be called without parentheses. The datepart passed to DATEDIFF will control the resolution of the output. 1239') returns 1. In Snowflake you can rewrite the query : SELECT datediff (day, '1900-01-01',. From fetching the current timestamp to calculating date differences, we've got you covered. You can only run them separately. ) @satitiru ,. functions. To comply with ANSI standards, this function can be called without parentheses. It is possible that there is something wrong in another part of the query. If the clicked date and the claimed date are set to '2999-12-31' then subtract deadline_date - bought_date. Calcule la différence entre deux expressions de date, d’heure ou d’horodatage en fonction de la date ou de l’heure demandée. functions. An image can help us visualize the concept you have, but the code is what you're trying to fix. Then you can run a fairly simple query: select t. snowflake. In SQL SERVER, you can use the following query (replace the date with your field): SELECT CASE WHEN datediff (year, '20120303', getdate ()) > 1 THEN datediff (year, '20120303', getdate ()) ELSE datediff (day, '20120303', getdate ()) END AS Diff. TIMESTAMP_LTZ. SELECT DATEADD(WEEK, DATEDIFF(WEEK,0,GETDATE()),-3) But based on my reading and some SQL Fiddle, it seems to output the start of "this week" minus 3 days. All datediff() does is compute the number of period boundaries crossed between two dates. 0. I managed to do it: use schema objectname. DATEDIFF (DAY/WEEK, START_DATE, END_DATE) will calculate difference, but the last date will be considered as END_DATE -1. Compare data tables between databases. Create the stored procedure. For instance, you can sub. Any fields using concatenation likely need to be modified. SQL Server Syntax DATEDIFF(datePart, date1, date2) The DATEDIFF() function in SQL Server has three required parameters:. From MySQL docs: DATEDIFF() returns expr1 − expr2 expressed as a value in days from one date to the other. A função retorna o resultado da subtração do segundo argumento do terceiro argumento. snowpark. Snowflake separates compute from storage, allowing for flexible pricing and configuration. Given the basic example,. SELECT DATEDIFF (month,'2011-03-07' , '2021-06-24'); In this above example, you can find the number of months between the date of starting and ending. 1 Answer. If you want to mimic hive logic in snowflake, you should use below code -. Expression to be converted into a time: For string_expr, the result of converting the string to a time. SQL; Snowflake; Timestamp +1 more; Like; Answer; Share; 1 answer; 1. If you want the difference, then use datediff () or timestampdiff (). I have attached the query with this comment. T. Want to elevate your date analytics in Snowflake?snowflake. startdate: The first date or datetime value. Unfortunately, the naive approach with the DATEDIFF () function doesn't quite cut it here - using DATEDIFF ('year', birthday, current_date) nets the difference between the current year and the birthday year, which could be a very inaccurate representation of the time between the two dates. Specifies the day of week used to calculate the date for the previous day. Snowflakeは、整数を秒として解釈することが意図されている場合にのみ、整数を含む文字列で TO. (varchar(10),(DATEDIFF(s,A. 9 and 2. select datediff ( day, Date ('Tue Jan 01 1980 00:00:00 GMT-0800 (Pacific Standard Time)')::timestamp, Date ('Tue Jan 01 2020 00:00:00 GMT-0800 (Pacific Standard Time)')::timestamp ); The function you mentioned will return the difference in days between the two dates specified. functions. A more general form of the question is Snowflake takes the simpler approach, and answer all units of date_diff in the difference of the values at the unit compared. Learn how to use the DATEDIFF () function to calculate the difference between dates, times, or timestamps in Snowflake. 6. 2021-06-10 12:07:04. insertedon,1,10))) There is any simple way to do this? just a subtraction of 2 hours to date time Regards. 2425):To get the number of month or day, you change the first argument to month or day as shown below: Notice that the DATEDIFF () function takes the leap year into account. Spark & PySpark SQL provides datediff() function to get the difference between two dates. Invalid function type [DATEDIFF] for window function. First. Calcula a diferença entre duas expressões de data, hora ou carimbo de data/hora com base na parte de data ou hora solicitada. The DATEDIFF command takes a datepart and returns the difference between two dates or timestamps. event_id, evnt. Postgres doesn’t have DATEDIFF(). 5 is rounded to -1. Here are some great date functions to round out your toolkit. Covering popular subjects like HTML, CSS, JavaScript, Python, SQL, Java, and many, many more. This is an expression that evaluates to a numeric data type (INTEGER, FLOAT, DECIMAL, etc. Cause. * from (select t. はじめに Snowflake の 日時(日付、時刻含む)について 少しづつだが、まとめておく。 目次 【1】日時(日付、時刻含む)のデータ型 【2】現在日時を返す関数 【3】日時(日付、時刻含む)の変換 1)キャスト 2)DATE_FROM_PARTS関数 【4】日時の計算 1)DATEADD関数 2)DATEDI…The date functions in Snowflake are same or slightly different compared to other RDBMS. I tried to define the correct start date with a SQL CASE before i start the AVG(DATEDIFF). HOUR. snowpark. The DATEDIFF () function returns an integer that represents the number of. Arguments. 함수 요약SELECT DATEDIFF(MINUTE, LAST_ALTERED, CURRENT_TIMESTAMP()) AS MINUTES_SINCE_LAST_UPDATE FROM MONITORING. 5 * FLOOR ((DATEDIFF (day, date_trunc ('quarter', @s), @e)). If the date part is a date, then the SQL DATEDIFF function sets the time part of the date to 00:00:00. This topic describes how to use the different types of window functions supported by Snowflake, including: General window functions. Hi @JustineMit - if an answer helps you, please upvote and/or accept it. Extracting the quarter date part from a timestamp returns the. functions. Mar 27, 2013 at 14:06. I have a table that contains all checkin dates for all users for a business. 要求された日付または時刻の部分に基づいて、2つの日付、時刻、またはタイムスタンプ式の差を計算します。この関数は、3番目の引数から2番目の引数を減算した結果を返します。 マイナス記号(-)を使用して日付を減算することもできます。If the datasource was previously pointing to SQL Server or DB2 and is now going to Snowflake, there might be some incorrect results when using the days_between. Thus select DATEDIFF('year', '2020-12-31', '2021-01-01') returns 1 because there's 1 year difference between 2020 and 2021, even though there's only actually 1 day between these 2 dates. All it does, is calculates the normal difference in days and then subtracts 2 (non-business) days from this result for each beginning of the week. Commonly used datepart units include month or second. * from (select t. 0 as HoursRoundedToHalfHour, Casting a datetime value to float gives you the number of days since a particular date. 1 Answer. See. Hour of the specified day. It covers all the basics, plus has the added feature of easily being able it to your warehouse with no storage cost. I usually get the error: Generator ROWCOUNT must be constant. We have these planned as future extensions. The minus sign (-) can also be used to subtract dates. nanosecond は、時、分、秒、および小数秒の9桁すべてを使用します. snowpark. For the 2-argument version: The source_timestamp argument is considered to include the time zone. From the inputs you got there are 123 months between the date of 07/03/2011 to 24/3/2021. functions. Thus select DATEDIFF('year', '2020-12-31', '2021-01-01') returns 1 because there's 1 year difference between 2020 and 2021, even though there's only actually 1 day between these 2 dates. For DATEDIFF: date_or_time_expr1 and date_or_time_expr2 can be a date, time, or timestamp. Replace () function helps to remove all the occurrences of a specified substring with input string. date_or_time_part 은 지원되는 날짜 및 시간 부분 에 나열된 값 중 하나. The Snowflake Search Optimization Service may also improve performance when working with high-cardinality dimension columns. Create an intermediate temporary table, e. I was changing : CONVERT(DATE, to date_trunc('DAY', GETUTCDATE(), to SYSDATE(),. You can even find the number of hours, minutes, seconds, and so on in terms of details in between the two. (Most window functions require at least one column or. Let’s look at the clear differences between the two. For example, SELECT DATEDIFF (day, '2036-03-01', '2036-02-28'); returns -2, hinting that 2036 must be a leap year. A general expression. functions. For DATEDIFF: date_or_time_expr1 and date_or_time_expr2 can be a date, time, or timestamp. SQL. g. TIMESTAMPDIFF. 3,330 3 3. Write resolution instructions: Use bullets, numbers and additional headings Add Screenshots to explain the resolution Add diagrams to explain complicated technical details, keep the diagrams in lucidchart or in google slide (keep it shared with entire Snowflake), and add the link of the source material in the Internal comment section Go in depth if required Add links and other resources as. The reason I like to do it this way, is because its flexible enough that I can add weekly, hourly, or monthly intervals between the dates and reuse the code. snowflake. select post_visid_high || ':' || post_visid_low as visitor_id , lag (date_time) over (partition by visitor_id order by date_time asc) as previous_date , datediff (minute, previous_date, date_time) as difference_in_minutes from adobe_data. Input: DAY ----- 2022-06-09 2022-04-04 Output DAY_MONTH -----. snowflake. The string must start with the first two characters (case-insensitive) of the day name: su (Sunday) mo (Monday) tu (Tuesday) we (Wednesday) th (Thursday)When using convert_timezone() to convert timestamps with no timezone to my local time, the function outputs a timestamp like (I'm converting from timestamp with no time zone UTC to MST):I initially had an issue with loading long timestamps (9999-12-31 23:59:59. Supported date and time parts. should work fine. ,DATEDIFF(SECOND, DATETIME_1, DATETIME_2) AS DIFF_SECONDS ,DIFF_SECONDS % (60) AS NUM_SECONDS. The following example illustrates how to use the. Snowflake. functions. Ask Mike anything about becoming a Data Superhero, building ML models, his journey as a global nomad, and more! snowflake. I have a use case that I need to run a sql code snippet in a stored procedure, I saw this post and I didn't see how I can utilize my code using the suggested solution. AWS Redshift clusters require some manual maintenance. 5401041667. A common business problem is calculating the number of working days or hours between two timestamps. The LAG () function is used to extend the delay or fall behind to perform an action. functions. Compared to true difference in values, and then that being expressed in a time unit. TIMESTAMP_TZ. One aproach to deal with division by zero is to use NULLIF. DATEDIFF(expr1,expr2) Use: SELECT DATEDIFF(___Bookings. snowflake. It is following snowflake's documentation. select t. It looks like the function DATEADD / DATEDIFF is causing it to fail: SET MONTH_DELTA = ABS (-1);--works; SET MONTH_DELTA = CURRENT_DATE;--works; SET MONTH_DELTA = DATEDIFF (month, '1900-01-01', '1901-01-01');--doesn 't work; In the Snowflake documentation it mentions that the result of an SQL expression can be set to the value of. How to assign output of a result set to a variable? Hi, I have a variable VAR_DATE, this variable has to be assigned with the value of a column in a result set. Dec 15, 2022 at 22:20. Default is 1. Snowflake supports date_trunc () for datatypes DATE, TIME, and TIMESTAMP: SELECT DATE_TRUNC (month, CURRENT_DATE ()) AS first_day_of_month; Sounds like you're working with strings. of days as: days start_date end_date 14 2022. schemaname. Show more actions. The DATEDIFF () function calculates the difference in days between two DATE values. It returns a number, not a date. If you then apply a further DATEADD () operation to that date, as in the. An aggregate function takes multiple rows (actually, zero, one, or more rows) as input and produces a single output. microsecond uses the hour, minute, second, and first six digits of the fractional seconds. If either the input_expr or the scale_expr is NULL, the result is NULL. Das Minuszeichen ( -) kann auch zum Subtrahieren von Datumsangaben verwendet werden. was asking for, but useful for those looking to generate a list of dates in Snowflake SQL. DATEDIFF: Calculate difference between two dates and return date part. When date_or_time_part is week (or any of its variations), the output is controlled by the WEEK_START session parameter. Please try a simpler expression. so you would expect to only get two rows if you use this logic in the filter, which is what happens. snowpark. I want to create Calendar Table in Snowflake which has start and end date as dynamic dates. I want to be able to compare the date between the first record and any future records for that card id where that future record's legit = 0, and if the first record is within 10 days, show that record. So I got help to get started on this and it runs well. functions. What is SUBSTRING () Function in Snowflake? SUBSTRING () function helps to get the substring from a string by providing the starting index and length of the substring. SQL Server : -- Get difference in days SELECT DATEDIFF ( dd, '2022-09-01', '2022-09-05'); # 4. Syntax For DATEDIFF DATEDIFF( <date_or_time_part>, <date_or_time_expr1>, <date_or_time_expr2> ) For minus sign <date_expr2> - <date_expr1> Arguments For. See the syntax, usage, and examples of this function with various date and time parts. This unit of measure must be one of the values listed in . For example, if we want to get the name ‘John’ from the name ‘John Rose’, then we can make use of this function as: substring (‘John Rose’,0,4). , CONVERT (date, DATEADD (month, DATEDIFF (month, 0, GETDATE ()), 0)) AS MTDStart--Month to Date Start, CONVERT (date, GETDATE ()) AS MTDEnd--Month to Date End; FROM #FY ; WHERE DATEPART (m, GETDATE ()) = [Month] Expand Post. functions. 29K views; Top. NAME FROM CUSTOMER C LEFT JOIN. Setting a clustering key is important on large fact tables. The datepart value cannot be specified in a variable, nor as a quoted string like 'month'. Usage Notes¶. snowpark. datediff¶. I will use floating point maths to make my point. datediff¶. HOWEVER, if the clicked date is not found (meaning it is set to: '2999-12-31') then take the deadline date - claimed date. The parameter group bounds changes the way the join happens in a. ほとんどのユースケースでは、Snowflakeは文字列としてフォーマットされた日付とタイムスタンプの値を正しく処理します。Some databases, such as Snowflake and BigQuery, support functions like DATEDIFF or DATE_DIFF. So try converting one of them to other timezone using "CONVERT_TIMEZONE" and thn apply the DATEDIFF function. Here is a brief and simplified extract of my current dataset: All my users currently have a start time and end time for various actions they complete. 999) from pqrquet file to snowflake. Snowflake Date Functions. functions. The syntax is different for every database: Snowflake, Postgres, MySQL, etc. Take the max of that filtered list, then join back to the original data to get the status for the row with the max value. This makes that answer appear right after the question so it's easier to find within a thread. functions. I am trying to get the same output in Snowflake, but cant figure out how to return a float. Must be one of the values listed in Supported Date and Time Parts (e. This allows, for example, choosing the N-th day in a year, which can be. 44597. 0. How exactly did you get this to work against. SELECT date1, date2 FROM (VALUES ('2020-01-02'::date, '2020-04-01'::date), ('2020-02-01'::date, '2020-03-09'::date), ('2021-01-04'::date, '2021-04-09'::date) v (date1, date2) ) WHERE abs (datediff ('days', date1, date2)) > 45 ; Now I used ABS. Then next new "min_date" = previous "next_date" until "DATEDIFF" is calculated. Dec 15, 2022 at 23:25. Invalid function type [TIMEDIFF] for window function. : create temp table dummy_1 (days int) as select datediff ('day', '2018-07-20', '2018-07-27'); 2. functions. The function returns the result of subtracting the second argument from the third argument. There is also now a calendar table available in the Snowflake Data Marketplace. Invalid function type [DATEDIFF] for window function. 997', '2013-06-01 21:59:59. Example:Usage Notes¶. YEAR* / DAY* / WEEK* / MONTH / QUARTER¶. The return value is always of type TIMESTAMP_TZ. In Snowflake, it is possible to run stored procedures within a transaction, which means that the changes made by the stored procedure are committed or rolled back as a single unit of work. Select (CASE when targetcompletedate <= NOW() the 'Overdue' else 'Days Left' end) If you want to show things as numbers, then you want the datediff(). The number of dateparts separating two date/time instances is too large You can use following method which is overflow-safe and gives you a float result:The syntax for using the DATEDIFF function in Snowflake and Amazon Redshift, and Databricks looks like the following: datediff (< date part >, < start date / time >, < end date / time >) Info: Databricks additionally supports a separate DATEDIFF function that takes only two arguments: a start date and an end date. 5401041667. DATEADD (HOUR, -48, DATEDIFF (HOURS, WL_SUBMIT_DATE_TIME, GETDATE ())) You calculate the time difference (in hours) between WL_SUBMIT_DATE_TIME and the current date. *, min (date) over (partition by cardid) as min_date from t ) t where legit = 0 and date < min_date + interval '10 day. DATETIME. Example: DATEDIFF on several events for specific value. SELECT AVG (DATEDIFF (d, DateUsed, DateExpires)) FROM tbl. convert(varchar,cast((End_Datetime-Start_Datetime) as time),108) how to convert this to snowflake snowflake. approx_percentile_combine. 117 3 11 DATEDIFF ( <date_or_time_part>, <date_or_time_expr1>, <date_or_time_expr2> ) If date_or_time_part is week (or any of its variations), the output. approx_percentile_combine. Returning Sum of all rows that fit date criteria.